Engineering Reference

Engineering Formula Chart

58 formulas grouped by subject — stress and strain, bending, torsion, columns, pressure, fluids, heat, machining, threads, gears, springs, bearings and fits — with what each variable means.

Data verified 2026-09-29 · based on Roark's, 8th edition (2011)

Engineering Formulas by Subject

Subject[1]Quantity[1]Formula[1]Variables[1]Notes[1]
Stress #Stressσ = F ÷ Aσ stress, F force, A cross-sectional areaBasic definition; the starting point for every strength check
Stress #Strainε = ΔL ÷ L₀ε strain, ΔL change in length, L₀ original lengthDimensionless; often quoted in microstrain (×10⁻⁶)
Stress #Hooke's lawσ = E · εE modulus of elasticityValid only below the proportional limit
Stress #Poisson's ratioν = −ε_lateral ÷ ε_axialTypically 0.3 for metals, 0.4 for plasticsWhy a bar gets thinner when pulled
Bending #Bending stressσ = M · c ÷ IM moment, c distance to extreme fibre, I second moment of areaAlso written σ = M ÷ S where S = I/c
Bending #Section modulusS = I ÷ cS elastic section modulusGoverns stress; I governs deflection
Bending #Beam deflection, central point loadδ = P · L³ ÷ (48 · E · I)P load, L spanSimply supported
Bending #Beam deflection, uniform loadδ = 5 · w · L⁴ ÷ (384 · E · I)w load per unit lengthSimply supported
Bending #Cantilever, end point loadδ = P · L³ ÷ (3 · E · I)P load, L lengthSame load and span as a simple beam gives 16× the deflection
Torsion #Torsional shear stressτ = T · r ÷ JT torque, r radius, J polar moment of inertiaMaximum at the outer surface
Torsion #Polar moment of inertia, solid shaftJ = π · d⁴ ÷ 32d shaft diameterTwice the planar moment of inertia
Torsion #Angle of twistθ = T · L ÷ (G · J)G shear modulus, L lengthθ in radians
Torsion #Power transmitted by a shaftP = 2π · n · T ÷ 60n rotational speed in rpm, T torque in N·mGives power in watts
Columns #Euler buckling loadPcr = π² · E · I ÷ (K · L)²K effective length factorValid while the buckling stress is below about half yield
Columns #Slenderness ratioλ = K · L ÷ rr radius of gyration = √(I/A)Governs whether buckling or yielding governs
Pressure #Hoop stress, thin cylinderσ = p · D ÷ (2 · t)p internal pressure, D diameter, t wallValid when t is under about a tenth of D
Pressure #Longitudinal stress, thin cylinderσ = p · D ÷ (4 · t)Half the hoop stressWhy a cylinder splits lengthwise, not around
Pressure #Spherical shell stressσ = p · D ÷ (4 · t)Uniform in all directionsHalf the hoop stress of a cylinder of the same size
Fluids #Reynolds numberRe = ρ · v · D ÷ µρ density, v velocity, D diameter, µ dynamic viscosityLaminar below ~2 300, turbulent above ~4 000
Fluids #Darcy-Weisbach pressure dropΔP = f · (L ÷ D) · ρ · v² ÷ 2f friction factorRises with the square of flow rate in turbulent flow
Fluids #Bernoulli's equationp + ½ρv² + ρgh = constanth elevationEnergy conservation along a streamline
Fluids #Flow through a pipeQ = A · vQ volumetric flow rateContinuity: what goes in comes out
Heat #Conduction, plane wallQ = k · A · ΔT ÷ tk thermal conductivity, t thicknessFourier's law
Heat #ConvectionQ = h · A · ΔTh convective heat transfer coefficientNewton's law of cooling
Heat #Sensible heatQ = m · cp · ΔTcp specific heat capacityThe heat to change temperature without a phase change
Heat #Thermal expansionΔL = L · α · ΔTα coefficient of linear thermal expansionRoughly 12 µm/m·°C for steel
Heat #Fin efficiency parameterm = √(h · P ÷ (k · A))P perimeter, A cross-sectionGoverns how far heat travels along a fin
Machining #Spindle speed from surface speedn = SFM × 3.82 ÷ DD tool diameter in inchesThe basic machine setting calculation
Machining #Surface speed from spindle speedSFM = π · D · n ÷ 12D in inches, n in rpmThe inverse relationship
Machining #Milling table feedF = fz · z · nfz feed per tooth, z number of teethIndependent of depth and width of cut
Machining #Material removal rate, millingMRR = ap · ae · Fap depth, ae width of cutVolume removed per minute
Machining #Theoretical surface roughness, turningRa ≈ f² ÷ (32 · r)f feed per rev, r tool nose radiusWhy feed matters more than speed for finish
Machining #Machining timeT = L ÷ FL length of cut, F feed rateAdd tool approach and retract for the actual cycle time
Threads #Metric tensile stress areaAs = π/4 · (d − 0.9382P)²d major diameter, P pitchISO 898-1 definition
Threads #Unified tensile stress areaAs = 0.7854 · (D − 0.9743/n)²D major diameter, n threads per inchASME definition; note the different coefficient
Threads #Pitch diameterd₂ = d − 0.64952 · PP pitchUnified and metric 60° threads
Threads #Tap drill, approximatedrill = d − Pd major diameter, P pitchGives about 75% thread engagement; round to the nearest standard drill
Electrical #Ohm's lawV = I · RV voltage, I current, R resistanceThe fundamental relationship of circuit analysis
Electrical #Power, resistiveP = V · I = I² · R = V² ÷ RP power in wattsWhich form to use depends on which two quantities are known
Electrical #Resistance of a conductorR = ρ · L ÷ Aρ resistivity, L length, A areaWhy long thin conductors drop more voltage
Electrical #Voltage drop, single phaseVd = 2 · ρ · L · I ÷ AThe 2 accounts for the return pathUse √3 instead of 2 for three-phase
Electrical #Three-phase powerP = √3 · V · I · PFPF power factorV is the line-to-line voltage
Gears #Gear ratioi = n_driven ÷ n_driverTeeth, not diametersSpeed divides by i; torque multiplies by it
Gears #Gear pitch diameterD = N ÷ DPN number of teeth, DP diametral pitchInches. For metric, D = N × module
Gears #Module from diametral pitchm = 25.4 ÷ DPm in millimetresReciprocal relationship — inch and metric gears do not interchange
Springs #Compression spring ratek = G · d⁴ ÷ (8 · D³ · N)G shear modulus, d wire diameter, D mean coil diameter, N active coilsWire diameter is to the fourth power
Springs #Spring forceF = k · xx deflectionHooke's law for a spring
Springs #Spring indexC = D ÷ dPractical range 4 to 12Governs manufacturability and stress concentration
Bearings #Bearing L10 lifeL10 = (C ÷ P)^p × 10⁶C dynamic rating, P equivalent load, p = 3 ball / 10/3 rollerLife in revolutions that 90% of bearings reach
Bearings #Bearing life in hoursL10h = L10 ÷ (60 · n)n speed in rpmThe figure used for selection
Fits #Interference from temperatureΔT = δ ÷ (α · D)δ diametral interference, α expansion coefficientFor shrink-fit assembly
Fits #Worst-case tolerance stackT = Σ tᵢSum of individual tolerancesGuaranteed; expensive
Fits #Statistical tolerance stackT = √(Σ tᵢ²)Root-sum-squareValid for centred, in-control processes only
Material #Weight of a sectionW = A · L · ρA area, L length, ρ densityUse kg/m³ with m, or lb/in³ with in
Material #Density from weight and volumeρ = m ÷ VThe definitionSteel is 7.85 g/cm³ = 0.2836 lb/in³
Material #Modulus from stress and strainE = σ ÷ εIn the linear region onlyRoughly 205 GPa for every steel
Material #Hardness to tensile, steelsUTS ≈ 500 × HB (MPa)Approximate, ±10%A rule of thumb, not a specification

Formulas are stated in consistent SI units unless the note says otherwise. Converting to imperial is not simply a matter of changing the numbers — several of these formulas carry constant coefficients that assume SI (Euler's buckling load, the thin-cylinder stresses, the deflection formulas in terms of E and I) and others carry coefficients that assume a particular unit system built into the constant, such as n = SFM × 3.82 ÷ D, where the 3.82 only works with inches and feet per minute.

Every formula here is an idealisation. Elastic formulas assume small deflections and a constant section; the thin-cylinder stresses assume a wall under a tenth of the diameter; Euler buckling assumes the stress at buckling is below about half the yield strength. Using a formula outside its assumptions is the most common source of a plausible but wrong answer.

The Three Formulas Worth Knowing by Heart

Most engineering estimates come down to three relationships, and knowing them makes it possible to check almost any number someone hands you.

σ = F ÷ A. Stress is force divided by area. It converts a load into a stress in one step, and comparing that stress against a yield strength is the first check on any part.

δ = P·L³ ÷ (48·E·I). Deflection of a simply supported beam under a central point load. The cube on the span and the fact that E·I sits underneath is the whole of beam design: span matters far more than load, and stiffness is a product of material and section.

P = 2π·n·T ÷ 60. Power from torque and speed. It is what connects a motor's rating to the torque available at a given speed, and it explains why a gearbox trades speed for torque while leaving power unchanged.

Everything else on this page is a variation on these three applied to a particular geometry or a particular physical process.

Unit Consistency Is Not Optional

More engineering answers are wrong because of units than because of physics. Three cases account for most of it.

Metres against millimetres. In deflection formulas the length is cubed, so a length entered in millimetres where metres were expected makes the answer wrong by 10⁹ — a factor of a billion. Always check the unit the formula's constant assumes.

Mass against force. The kilogram is a mass and the newton is a force, related by g = 9.80665 m/s². Treating a kilogram-force as a newton understates a load by roughly a factor of ten. The same trap exists in imperial units between the pound and the pound-force, though there the two are numerically equal under standard gravity and the error is easier to miss.

Hard-coded constants. Some constants in these formulas are unit conversions in disguise. The 3.82 in the milling speed formula, the √3 in three-phase power, and the 0.7854 in the unified stress area are all unit-specific. Substitute a different unit system and the constant changes even though the physics does not.

Frequently Asked Questions

What is the formula for bending stress?
σ = M·c ÷ I, where M is the bending moment, c the distance from the neutral axis to the extreme fibre and I the second moment of area. It is more often written σ = M ÷ S, where S = I/c is the section modulus — a tabulated property for standard sections.
What is the beam deflection formula?
For a simply supported beam with a central point load, δ = P·L³/(48·E·I). For a uniformly distributed load it is 5w·L⁴/(384·E·I), and for a cantilever with an end load it is P·L³/(3·E·I). All three carry the cube of span, which is why span drives section size so strongly.
How do I calculate spindle speed?
n = SFM × 3.82 ÷ D, where D is the tool diameter in inches. Going the other way, SFM = π·D·n ÷ 12. The 3.82 is the constant 12/π, so the formula only works with surface speed in feet per minute and diameter in inches.
What is the difference between stress and strain?
Stress is force per unit area, in pascals or psi. Strain is the fractional change in length, dimensionless. They are related by Hooke's law, σ = E·ε, but only below the proportional limit — past yield the relationship stops being linear and the formula no longer applies.
How do I convert torque to power?
P = 2π·n·T ÷ 60 with n in rpm and T in newton-metres, giving watts. In imperial units, horsepower = torque in lb·ft × rpm ÷ 5,252. The two constants differ because the unit systems do — the underlying relationship is the same.
Can I use these formulas with imperial units?
Not without changing the constants. Several formulas carry unit-specific coefficients: the 3.82 in the spindle speed formula, the √3 in three-phase power, and the different coefficients in the metric and unified tensile stress areas. The physics is the same but the constant is not — always check what units a formula's coefficient assumes.

Related

Value Sources

Each data column on this page is tied to the source it came from. The numbers in square brackets correspond to the table headers above.

#SourceTypeRevision / method
[1]Published handbook mechanical properties for engineering materialsstandardcompilations as published 2024–2026

Data Sources

StandardRevisionWhat it covers on this page
Roark's Formulas for Stress and StrainRoark's, 8th edition (2011)the stress, bending, torsion and column formulas
Shigley's Mechanical Engineering DesignShigley's, 11th edition (2020)the power transmission, gear, spring and bearing formulas
ASME B1.1 and ISO 898-1ASME B1.1-2019, ISO 898-1:2013the thread stress area and pitch diameter formulas

Cross-checked against:

Formulas are idealisations with stated assumptions — small deflections, constant section, stress below the proportional limit for elastic formulas, thin walls for the cylinder stresses. Constants embedded in some formulas are unit-system specific. Where a value will be used for design or acceptance, verify it against the governing standard rather than relying on a reference formula.

Accuracy and use. The values on this page are compiled from the published standards and cross-checked sources listed above. Where values are derived, the derivation is stated. No warranty, express or implied, is made as to the accuracy or completeness of this information, and no liability is accepted for any loss or damage arising from its use. Engineering reference data is provided for guidance in preliminary work — before a value is used for design, fabrication or acceptance testing, verify it against the current revision of the governing standard and against your own inspection. The user assumes all risk and responsibility in connection with the use of this information.

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